P is not equal to NP

نویسنده

  • Craig Alan Feinstein
چکیده

SAT is not in P is proved, in a first-order theory, with a new single finite axiom of Turing’s theory of computing. So, P is not equal to NP.

برای دانلود متن کامل این مقاله و بیش از 32 میلیون مقاله دیگر ابتدا ثبت نام کنید

ثبت نام

اگر عضو سایت هستید لطفا وارد حساب کاربری خود شوید

منابع مشابه

P is not equal to NP

A new axiom of Turing’s theory of computing is used to prove that SAT is not in P. Thus, P is not equal to NP, follows directly. A computeroriented version verifies the results, elsewhere, using a theorem-prover.

متن کامل

Philosophical Solution to P=?NP: P is Equal to NP

The P=?NP problem is philosophically solved by showing P is equal to NP in the random access with unit multiply (MRAM) model. It is shown that the MRAM model empirically best models computation hardness. The P=?NP problem is shown to be a scientific rather than a mathematical problem. The assumptions involved in the current definition of the P?=NP problem as a problem involving non deterministi...

متن کامل

Does NP not equal P ? C

— Stephen Cook posited SAT is NP-Complete in 1971. If SAT is NP-Complete then, as is generally accepted, any polynomial solution of it must also present a polynomial solution of all NP decision problems. It is here argued, however, that NP is not of necessity equivalent to P, were it shown that SAT is contained in P. This due to a paradox, of nature addressed by both Gödel and Russell, in regar...

متن کامل

P = Np

The question of whether the class of decision problems that can be solved by deterministic polynomial-time algorithms (P ) is equal to the class of decision problems that can be solved by nondeterministic polynomial-time algorithms (NP) has been open since it was first formulated by Cook, Karp, and Levin in 1971. In this paper, we prove that they are not equal by showing that any algorithm that...

متن کامل

P is not equal to NP by Modus Tollens

An artificially designed Turing Machine algorithm Mo generates the instances of the satisfiability problem, and check their satisfiability. Under the assumption P = NP , we show that Mo has a certain property, which, without the assumption, Mo does not have. This leads to P 6= NP by

متن کامل

ذخیره در منابع من


  با ذخیره ی این منبع در منابع من، دسترسی به آن را برای استفاده های بعدی آسان تر کنید

برای دانلود متن کامل این مقاله و بیش از 32 میلیون مقاله دیگر ابتدا ثبت نام کنید

ثبت نام

اگر عضو سایت هستید لطفا وارد حساب کاربری خود شوید

عنوان ژورنال:
  • CoRR

دوره cs.CC/0305035  شماره 

صفحات  -

تاریخ انتشار 2003