نتایج جستجو برای: Z(M)-inverse split module

تعداد نتایج: 204902  

Let M be a right module over a ring R. In this manuscript, we shall study on a special case of F-inverse split modules where F is a fully invariant submodule of M introduced in [12]. We say M is Z 2(M)-inverse split provided f^(-1)(Z2(M)) is a direct summand of M for each endomorphism f of M. We prove that M is Z2(M)-inverse split if and only if M is a direct...

2009
Quanlei Fang Jingbo Xia

Let H(S) be the Hardy space on the unit sphere S in C, n ≥ 2. Then H(S) is a natural Hilbert module over the ball algebra A(B). Let Mz1 , ..., Mzn be the module operators corresponding to the multiplication by the coordinated functions. Each submodule M ⊂ H(S) gives rise to the module operators ZM,j = Mzj |M, j = 1, ..., n, on M. In this paper we establish the following commonly believed, but n...

Journal: :نظریه تقریب و کاربرد های آن 0
abasalt bodaghi department of mathematics, islamic azad university, garmsar branch, garmsar, iran.

in this paper, we nd the relationships between module contractibility of abanach algebra and its ideals. we also prove that module contractibility ofa banach algebra is equivalent to module contractibility of its module uniti-zation. finally, we show that when a maximal group homomorphic image ofan inverse semigroup s with the set of idempotents e is nite, the moduleprojective tensor product ...

Journal: :bulletin of the iranian mathematical society 2011
e. nasrabadi a. pourabbas

let $s$ be an inverse semigroup and let $e$ be its subsemigroup of idempotents. in this paper we define the $n$-th module cohomology group of banach algebras and show that the first module cohomology group $hh^1_{ell^1(e)}(ell^1(s),ell^1(s)^{(n)})$ is zero, for every odd $ninmathbb{n}$. next, for a clifford semigroup $s$ we show that $hh^2_{ell^1(e)}(ell^1(s),ell^1(s)^{(n)})$ is a banach space,...

Journal: :bulletin of the iranian mathematical society 2013
h. pourmahmood-aghababa a. bodaghi

in the present paper, the concepts of module (uniform) approximate amenability and contractibility of banach algebras that are modules over another banach algebra, are introduced. the general theory is developed and some hereditary properties are given. in analogy with the banach algebraic approximate amenability, it is shown that module approximate amenability and contractibility are the same ...

1998
David M. Smith

The ZM package is a collection of Fortran subroutines that performs floating point multiple precision evaluation of complex arithmetic and elementary functions. These routines use the FM package [7] for real multiple precision arithmetic, constants, and elementary functions. Brent’s MP package [4] did not support complex arithmetic, and Bailey’s more recent MP package [2,3] provides complex ari...

2009
ANDREW M. BRUNNER SAID N. SIDKI

The group Am of automophisms of a one-rooted m-ary tree admits a diagonal monomorphism which we denote by x. Let A be an abelian state-closed (or self-similar) subgroup of Am. We prove that the recurrence and tree-topological closure A∗ of A is additively a finitely presented Zm [[x]]module where Zm is the ring of m-adic integers. Moreover, if A∗ is torsion-free then it is a finitely generated ...

In this paper, we nd the relationships between module contractibility of aBanach algebra and its ideals. We also prove that module contractibility ofa Banach algebra is equivalent to module contractibility of its module uniti-zation. Finally, we show that when a maximal group homomorphic image ofan inverse semigroup S with the set of idempotents E is nite, the moduleprojective tensor product l1...

Journal: :bulletin of the iranian mathematical society 2013
g. j. song

some necessary and sufficient conditions are given for the existence of a g-positive (g-repositive) solution to adjointable operator equations $ax=c,axa^{left( astright) }=c$ and $axb=c$ over hilbert $c^{ast}$-modules, respectively. moreover, the expressions of these general g-positive (g-repositive) solutions are also derived. some of the findings of this paper extend some known results in the...

2006
M. J. Fischer

that is, d is e−1 (the inverse of e) in Zφ(n). We now turn to the question of how Alice chooses e and d to satisfy (1). One way she can do this is to choose a random integer e ∈ Zφ(n) and then solve (1) for d. We will show how to solve for d in Sections 46 and 47 below. However, there is another issue, namely, how does Alice find random e ∈ Zφ(n)? If Z ∗ φ(n) is large enough, then she can just ...

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