Consider the following symmetric encryption scheme (KG , E,D). KG chooses an AES key. E(k,m) := EAES (k,m)‖032. (032 stands for a string consisting of 32 zeros.) And the decryption D(k, c) does the following: Let c′‖p := c where p has length 32 bit and c′ is all but the last 32 bits of c. m := DAES (k, c′). If p = 032, then D(k, c) returns m. If p 6= 032 and kp = 0 (here kp is the p-th bit of t...