We state a conjecture on the reduction modulo defining characteristic of unipotent representation finite reductive group.

A quantitative analysis of zone-specific proliferation was done to determine the recovery of adrenal cortical zonation during regeneration after enucleation. Adult male rats underwent adrenal enucleation [unilateral enucleation (ULE)] or sham surgery, both accompanied by contralateral adrenalectomy. At 2, 5, 10, and 28 days, blood and adrenals were collected to assess functional recovery. Adren...

A ia* number of aiQorithms haw been developed to compute the transitive cbaure of a database relation. Thir paper presents two new strategies that furlher reduce the data size dynamlcatly durtng the ocmputatbn and rpeed up the cowergence b the least fixed pdnt of Uw bansittve dosum reiation. A hash-based algorithm Utat in&grates hese new strategies Is then devebped. The performance analysh Mcat...

China has enacted the ultra-low emission (ULE) transform in coal-fired power plants. Various studies have focused on model simulation of pollutant variations a national scale, while specific data for concrete generation unit was still lacking. We deployed five-year online collection campaign 660 MW to investigate durative reductions dust, NOx, and SO2, increases removal efficiencies. The result...

We shall call a simple abelian variety A/Q modular if it is isogenous (over Q) to a factor of the Jacobian of a modular curve. In this paper we shall call a representation ρ̄ : GQ→GL2(F̄l) modular if there is a modular abelian variety A/Q, a number field F/Q of degree equal to dimA, an embedding OF ↪→ End(A/Q) and a homomorphism θ : OF→F̄l such that ρ̄ is equivalent to the action of GQ on the ker θ...

(i) Since 32 = 9 = 7 · 1 + 2, then we clearly have 32 mod 7 = 9 mod 7 = 2. (ii) The solution is easy found by inspection: We have 4 · 4 mod 15 = 16 mod 15 = 1, and thus 4−1 mod 15 = 4. (iii) I have seen many complicated solutions here, but the solution is very simple, and uses the fact that 32 mod 8 = 9 mod 8 = 1. Then, we use the fact (discussed in class) that a · b mod n = (a mod n) · (b mod ...