نتایج جستجو برای: whenever r divides n

تعداد نتایج: 1334461  

Journal: :Arch. Math. Log. 1997
Søren Riis

For each p ≤ 2 there exist a model M∗ of I∆0(α) which satisfies the Count(p) principle. Furthermore if p contain all prime factors of q there exist n, r ∈ M∗ and a bijective map f ∈ Set(M∗) mapping {1, 2, ..., n} onto {1, 2, ..., n+ qr}. A corollary is a complete classification of the Count(q) versus Count(p) problem. Another corollary solves an open question ([3]). In this note I state and pro...

2004
Piotr Rudnicki

We present a formalization of the factor theorem for univariate polynomials, also called the (little) Bezout theorem: Let r belong to a commutative ring L and p(x) be a polynomial over L. Then x− r divides p(x) iff p(r) = 0. We also prove some consequences of this theorem like that any non zero polynomial of degree n over an algebraically closed integral domain has n (non necessarily distinct) ...

Journal: :Canadian Journal of Mathematics 2023

Abstract Let G be a compact connected Lie group, and let $\operatorname {Hom}({\mathbb {Z}}^m,G)$ the space of pairwise commuting m -tuples in . We study problem which primes $p \operatorname {Z}}^m,G)_1$ , component containing element $(1,\ldots ,1)$ has p -torsion homology. will prove that for $m\ge 2$ homology if only divides order Weyl group $G=SU(n)$ some exceptional groups. also compute t...

Journal: :J. Comb. Theory, Ser. A 2002
Øystein J. Rødseth James A. Sellers

The restricted binary partition function bk(n) enumerates the number of ways to represent n as n = 2a0 + 2a1 + · · ·+ 2aj with 0 ≤ a0 ≤ a1 ≤ . . . ≤ aj < k. We study the question of how large a power of 2 divides the difference bk(2n) − bk−2(2n) for fixed k ≥ 3, r ≥ 1, and all n ≥ 1.

1970
P. Erdös

Let al <. .. < ak s n be a sequence of integers no one of which divides any other. It 1s not difficult to see that max k-[Et'-) [1]. Assume now that no a i divides the product of two others, then I proved that [2] (r(x) denotes the number of primes c x2/3 (1) n (x) +-l Z < max k (t .9 =) not exceeding x) x 2/3 < e(x) + c 2 (tog =) 2 The proof of both the upper and the lower bound used combinato...

Journal: :Journal of Combinatorial Designs 2021

It is well known that, whenever k divides n, the complete k-uniform hypergraph on n vertices can be partitioned into disjoint perfect matchings. Equivalently, set of k-subsets an n-set parallel classes so that each class a partition n-set. This result as Baranyai's theorem, which guarantees existence Baranyai partitions. Unfortunately, proof theorem uses network flow arguments, making this none...

Journal: :Electr. J. Comb. 1997
Michael Avidon

A primitive 3-smooth partition of n is a representation of n as the sum of numbers of the form 2a3b, where no summand divides another. Partial results are obtained in the problem of determining the maximal and average order of the number of such representations. Results are also obtained regarding the size of the terms in such a representation, resolving questions of Erdős and Selfridge. 0. Int...

2004
PAUL ERDŐS

Note that, by (4 .4) and (4 .5), (7 .6) holds for all nonnegatíve p. Substituting from (7 .6) in (6 .1) and (6 .2) and evaluating coefficients of xm, we obtain the following two identities. r-1 m (p + q)T rP~+4) = pTrpm + ~,(q) + T (P)-L q r, m pq E a l i r-a-1, m-j s-0 j-0 r-1 m-1 pq ~-~ T(P)Tr(9a-l. m-i-1 a L-0 i-0 r-1 m (r + i)Tr m+q) _ (r + 1)Tr + p (r-s)T (P)T (q) a. j r-8-1, M-j 8-0 j-0 r...

Journal: :International Journal of Number Theory 2022

Let [Formula: see text] be a Lucas sequence and, for every prime number text], let the rank of appearance in that is, smallest positive integer such divides whenever it exists. Furthermore, an odd integer. Under some mild hypotheses, we prove asymptotic formula primes as text].

Journal: :Beiträge Zur Algebra Und Geometrie / Contributions To Algebra And Geometry 2021

Let $X$ be a nonempty set. Denote by $\mathcal{F}^n_k$ the class of associative operations $F\colon X^n\to X$ satisfying condition $F(x_1,\ldots,x_n)\in\{x_1,\ldots,x_n\}$ whenever at least $k$ elements $x_1,\ldots,x_n$ are equal to each other. The $\mathcal{F}^n_1$ said quasitrivial and those $\mathcal{F}^n_n$ idempotent. We show that $\mathcal{F}^n_1=\cdots =\mathcal{F}^n_{n-2}\subseteq\mathc...

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