نتایج جستجو برای: cos

تعداد نتایج: 8148  

2015
Kerry Avery Katy Chalmers Katie Whale Natalie Blencowe Rhiannon Macefield Sara Brookes Chris Metcalfe Jane Blazeby

Background Core outcome sets (COS) seek to overcome heterogeneity in outcome reporting by generating outcomes to be measured and reported as a minimum in all trials of specific conditions. Patients’ views are integral to this but less is understood about selecting which healthcare professionals to be involved. We examined whether differences in the health professionals surveyed influenced outco...

Journal: :CAIS 2016
Acklesh Prasad Peter F. Green

There is an uptake of organizations’ involvement in collaborative organizational structures (COS). Consistent with the resource-centric views of the firm, we suggest that the COS members need to contribute their managed IT competencies to their COS, whose synergies would create COS IT competencies. We suggest three key IT competencies for COS: proactive top management decision synergy, collabor...

2004
Predrag Cvitanović Glen Robinson Leonid A. Bunimovich

Faculty: Y.H. Chen, Associate Professor, School of Mechanical Engineering (COE) R.F. Fox, Regents’ Professor, Chair of School of Physics (COS) R. Grigoriev, Assistant Professor, School of Physics (COS) E.M. Harrell, Professor, School of Mathematics(COS) C.A. Klausmeier, Assistant Professor, School of Biology (COS) P.J. Mucha, Assistant Professor, School of Mathematics (COS) G.P. Neitzel, Profes...

Journal: :The Ulster Medical Journal 1971
J. H. Biggart

SET in the azure Aegean sea is the island of Cos. Not far to the east is a promontory on which was once the city of Cnidos. Both were inhabited by Greeks, yet even as in our own country Greek did not always agree with Greek, and differing solutions to the same problem often led to considerable variation in opinion. Yet here in these two small land areas took origin some of the very basic concep...

2006
Boaz Barak

This document includes some mathematical notions I will assume. Most of these are taught in a discrete math class, and in any case are not complicated and easy to pick up. You can read it at your own pace — it will take a few weeks until we’ll get to use all of this stuff. You do not have to do the exercises, and in any case don’t need to submit them. If you feel you’d like more clarifications ...

2006

deal effectively with the increased density of the pork industry in some areas and the increased public concerns regarding nutrient excretion and odour emissions. Successful management of nitrogen and phosphorus is key for sustainable pork production to address these public concerns. For example, nitrogen excretion in the form of ammonia is a concern because of its impact on the work environmen...

2016
W. Sun U. Seibt

Soil exchange of carbonyl sulfide (COS) is the second largest COS flux in terrestrial ecosystems. A novel application of COS is the separation of gross primary productivity (GPP) from concomitant respiration. This method requires that soil COS exchange is relatively small and can be well quantified. Existing models for soil COS flux have incorporated empirical temperature and moisture functions...

2010

5 . (b) Applying the product rule, we have ((1 + 4x)e−4x)′ = (1 + 4x)′e−4x + (1 + 4x)(e−4x)′ = 4e−4x + (1 + 4x)e−4x(−4x)′ = 4e−4x + (1 + 4x)e−4x(−4) = 4e−4x − 4e−4x − 16xe−4x = −16xe−4x. (c) [(sec(x) + tan(x))3]′ = 3(sec(x) + tan(x))(sec(x) + tan(x))′ = 3(sec(x) + tan(x))(sec(x) tan(x) + sec(x)) = 3(sec(x) + tan(x)) · sec(x) · (sec(x) + sec(x)) = 3 sec(x)(sec(x) + tan(x)). (d)(x cos(x)− 6x sin(...

2006

6 = 2(cos( (π+2kπ) 6 ) + i sin( (π+2kπ) 6 )) where k = 0, 1, 2, · · · , 5. Let rk = 2(cos( (π+2kπ) 6 ) + i sin( (π+2kπ) 6 )) where k = 0, 1, 2, · · · , 5. Therefore r0 = 2(cos( π 6 )+i sin( 6 )) = √ 3+i, r1 = 2(cos( π 2 )+i sin( 2 )) = 2i, r2 = 2(cos( 5π 6 )+ i sin( 6 )) = − √ 3 + i, r3 = 2(cos( 7π 6 ) + i sin( 6 )) = − √ 3 − i, r4 = 2(cos( 2 ) + i sin( 2 )) = −2i and r5 = 2(cos( 6 ) + i sin( 1...

2005

6 = 2(cos( (π+2kπ) 6 ) + i sin( (π+2kπ) 6 )) where k = 0, 1, 2, · · · , 5. Let rk = 2(cos( (π+2kπ) 6 ) + i sin( (π+2kπ) 6 )) where k = 0, 1, 2, · · · , 5. Therefore r0 = 2(cos( π 6 )+i sin( 6 )) = √ 3+i, r1 = 2(cos( π 2 )+i sin( 2 )) = 2i, r2 = 2(cos( 5π 6 )+ i sin( 6 )) = − √ 3 + i, r3 = 2(cos( 7π 6 ) + i sin( 6 )) = − √ 3 − i, r4 = 2(cos( 2 ) + i sin( 2 )) = −2i and r5 = 2(cos( 6 ) + i sin( 1...

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