نتایج جستجو برای: abelian simple group
تعداد نتایج: 1414118 فیلتر نتایج به سال:
the purpose of the present study was to see which one of the two instruction-processing instruction (pi) and meaningful output based instruction (mobi) accompanied with prompt and recast- is more effective on efl learners’ writing accuracy. in order to homogenize the participants in term of language proficiency a preliminary english test (pet) was administrated between 74 intermediate students ...
We prove that a non-abelian superstable CSA-group has an infinite definable simple subgroup all of whose proper definable subgroups are abelian. This imply in particular that the existence of non-abelian CSAgroup of finite Morley rank is equivalent to the existence of a simple bad group all whose definable proper subgroups are abelian. We give a new proof of a result of E. Mustafin and B. Poiza...
One of the main aims of workers in the theory of groups has always been the determination of all finite simple groups. For simple groups may be regarded as the fundamental building blocks out of which finite groups are constructed. The cyclic groups of prime order are trivial examples of simple groups, and are the only simple groups which are Abelian. The first examples of non-Abelian simple gr...
let $g$ be a finite group. in [ghasemabadi et al., characterizations of the simple group ${}^2d_n(3)$ by prime graph and spectrum, monatsh math., 2011] it is proved that if $n$ is odd, then ${}^2d _n(3)$ is recognizable by prime graph and also by element orders. in this paper we prove that if $n$ is even, then $d={}^2d_{n}(3)$ is quasirecognizable by prime graph, i.e...
A 2-Sylow subgroup of J is elementary abelian of order 8 and J has no subgroup of index 2. If r is an involution in J, then C(r) = (r) X K, where K _ A5. Let G be a finite group with the following properties: (a) S2-subgroups of G are abelian; (b) G has no subgroup of index 2; and (c) G contains an involution t such that 0(t) = (t) X F, where F A5. Then G is a (new) simple group isomorphic to J...
let $g$ be a group and $aut(g)$ be the group of automorphisms of$g$. for any naturalnumber $m$, the $m^{th}$-autocommutator subgroup of $g$ is definedas: $$k_{m}(g)=langle[g,alpha_{1},ldots,alpha_{m}] |gin g,alpha_{1},ldots,alpha_{m}in aut(g)rangle.$$in this paper, we obtain the $m^{th}$-autocommutator subgroup ofall finite abelian groups.
a $p$-group $g$ is $p$-central if $g^{p}le z(g)$, and $g$ is $p^{2}$-abelian if $(xy)^{p^{2}}=x^{p^{2}}y^{p^{2}}$ for all $x,yin g$. we prove that for $g$ a finite $p^{2}$-abelian $p$-central $p$-group, excluding certain cases, the order of $g$ divides the order of $text{aut}(g)$.
let $gamma$ be a normal subgroup of the full automorphism group $aut(g)$ of a group $g$, and assume that $inn(g)leq gamma$. an endomorphism $sigma$ of $g$ is said to be {it $gamma$-central} if $sigma$ induces the the identity on the factor group $g/c_g(gamma)$. clearly, if $gamma=inn(g)$, then a $gamma$-central endomorphism is a {it central} endomorphism. in this article the conditi...
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