نتایج جستجو برای: q order
تعداد نتایج: 1012443 فیلتر نتایج به سال:
In this paper, we propose a modification of the second order method introduced in [Q. Li and X. Y. Wu, A two-step explicit $P$-stable method for solving second order initial value problems, textit{Appl. Math. Comput.} {138} (2003), no. 2-3, 435--442] for the numerical solution of IVPs for second order ODEs. The numerical results obtained by the new method for some...
In this article, we develop the distributed order fractional hybrid differential equations (DOFHDEs) with linear perturbations involving the fractional Riemann-Liouville derivative of order $0 < q < 1$ with respect to a nonnegative density function. Furthermore, an existence theorem for the fractional hybrid differential equations of distributed order is proved under the mixed $varphi$-Lipschit...
1. Examples Example 1.1. The field extension Q(√ 2, √ 3)/Q is Galois of degree 4, so its Galois group has order 4. The elements of the Galois group are determined by their values on √ 2 and √ 3. The Q-conjugates of √ 2 and √ 3 are ± √ 2 and ± √ 3, so we get at most four possible automorphisms in the Galois group. See Table 1. Since the Galois group has order 4, these 4 possible assignments of v...
Let q be a power of 2. We show by representation theory that there exists a q × q unitary matrix of multiplicative order q + 1 whose powers generate q + 1 complex pairwise mutually unbiased bases in C. When q is a power of an odd prime, there is a q × q unitary matrix of multiplicative order q+1 whose first (q+1)/2 powers generate (q+1)/2 complex pairwise mutually unbiased bases. We also show h...
0 −−−−→ {O, (0, 0)} −−−−→ E(Q) φ −−−−→ E(Q) α −−−−→ Q×/Q× 2 0 −−−−→ {O, (0, 0)} −−−−→ E(Q) ψ −−−−→ E(Q) β −−−−→ Q×/Q× . Finally, we have ψ ◦ φ = [2]E (multiplication by 2 on E) and φ ◦ ψ = [2]E. Thus although the situation is more involved than for the 2-descent on curves with three rational points of order 2, we have managed to break up the multiplicationby-2 map into two homomorphisms φ and ψ...
where v ranges over all places of Q and Qv is the completion of Q at v, denote its TateShafarevich group. As usual, L(E/Q, s) is the complex L-function of E over Q. Since E is now known to be modular, Kolyvagin’s work [11] shows that X(E/Q) is finite if L(E/Q, s) has a zero at s = 1 of order ≤ 1, and that gE/Q is equal to the order of the zero of L(E/Q, s) at s = 1. His proof relies heavily on ...
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