Correspondence Arthur A. Berberian Laboratório Interdisciplinar de Neurociências Clínicas, Centro de Estudos, Universidade Federal de São Paulo Rua Dr Bacelar, 334 04026-001 São Paulo, SP, Brazil Phone/Fax: (+55 11) 5539-1468 / 5083-2371 E-mail: [email protected] Arthur A. Berberian,1,2 Bruna T. Trevisan,3 Tais S. Moriyama,1,2,4 José M. Montiel,5 José Ari C. Oliveira,5,6 Alessandra G. Seabra3

s of Papers, 222nd ACS National Meeting, Chicago, IL, United States,August 26-30, 2001 2001, PMSE-366.(33) Lee, S.-H.; Ku, B.-C.; Wang, X.; Samuelson, L. A.; Kumar, J. MaterialsResearch Society Symposium Proceedings 2002, 708, 403-408.(34) Zhang, Y.; Dong, H.; Norris, I. D.; MacDiarmid, A. G.; Jones, W. E., Jr. Abstracts of Papers, 222nd ACS National Meeting, Chicago, IL, United...

Let $G$ be a $p$-group of nilpotency class $k$ with finite exponent $exp(G)$ and let $m=lfloorlog_pk floor$. We show that $exp(M^{(c)}(G))$ divides $exp(G)p^{m(k-1)}$, for all $cgeq1$, where $M^{(c)}(G)$ denotes the c-nilpotent multiplier of $G$. This implies that $exp( M(G))$ divides $exp(G)$, for all finite $p$-groups of class at most $p-1$. Moreover, we show that our result is an improvement...

let $g$ be a $p$-group of nilpotency class $k$ with finite exponent $exp(g)$ and let $m=lfloorlog_pk floor$. we show that $exp(m^{(c)}(g))$ divides $exp(g)p^{m(k-1)}$, for all $cgeq1$, where $m^{(c)}(g)$ denotes the c-nilpotent multiplier of $g$. this implies that $exp( m(g))$ divides $exp(g)$, for all finite $p$-groups of class at most $p-1$. moreover, we show that our result is an improvement...

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