We provide another proof of the Sipser{Lautemann Theorem by which BPP MA (PH). The current proof is based on strong results regarding the ampliication of BPP, due to Zuck-erman. Given these results, the current proof is even simpler than previous ones. Furthermore, extending the proof leads to two results regarding MA: MA ZPP NP (which seems to be new), and that two-sided error MA equals MA. Fi...