If instead the tangents to C1 at P1, P2 are not perpendicular to L, then we claim there cannot be any point where C1 and C2 are tangent. Indeed, if we count intersections of C1 and C2 (by using C1 to substitute for y in C2, then solving for y), we get at most four solutions counting multiplicity. Two of these are P1 and P2, and any point of tangency counts for two more. However, off of L, any p...