نتایج جستجو برای: digraphs
تعداد نتایج: 5018 فیلتر نتایج به سال:
We study the shortest-path broadcast problem in graphs and digraphs, where amessage has to be transmitted from a source node s to all the nodes along shortest paths, in the classical telephonemodel. For both graphs and digraphs, we show that the problem is equivalent to the broadcast problem in layered directed graphs. We then prove that this latter problem is NP-hard, and therefore that the sh...
We consider a notion of embedding digraphs on orientable surfaces, applicable to digraphs in which the indegree equals the outdegree for every vertex, i.e., Eulerian digraphs. This idea has been considered before in the context of “compatible Euler tours” or “orthogonal A-trails” by Andsersen at al [1] and by Bouchet [4]. This prior work has mostly been limited to embeddings of Eulerian digraph...
In this paper we present some new sufficient conditions for equality of edge-connectivity and minimum degree of graphs and digraphs as well as of bipartite graphs and digraphs.
In this paper, we completely determine the connectivity of every infinite circulant digraphs and prove that almost all infinite circulant digraphs are infinitely strongly connected and therefore have both oneand two-way infinite Hamiltonian paths.
let $d$ be a digraph with skew-adjacency matrix $s(d)$. the skew energy of $d$ is defined as the sum of the norms of all eigenvalues of $s(d)$. two digraphs are said to be skew equienergetic if their skew energies are equal. we establish an expression for the characteristic polynomial of the skew adjacency matrix of the join of two digraphs, and for the respective skew energ...
Given a digraph D, the Minimum Leaf Out-Branching problem (MinLOB) is the problem of finding in D an out-branching with the minimum possible number of leaves, i.e., vertices of out-degree 0. Gutin, Razgon and Kim (2008) proved that MinLOB is polynomial time solvable for acyclic digraphs which are exactly the digraphs of directed path-width (DAG-width, directed tree-width, respectively) 0. We in...
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