نتایج جستجو برای: new criteria

تعداد نتایج: 2067177  

Journal: :Journal of the American College of Radiology 2017

Journal: :genetics in the 3rd millennium 0
مازیار سیدیان maziar seyedian tehran university of medical sciences, tehran, iranاستاد یار نورولوژی، دانشگاه علوم پزشکی تهران، تهران، ایران

alzheimers disease (ad) is by far the most common cause of dementia. definite diagnosis of ad is based on pathological findings. nincds-adrda criteria, published more than 25 years ago, are commonly used for the clinical diagnosis of ad. however, considering serious shortcomings of these criteria, new criteria have been proposed. according to these new criteria, ad can be diagnosed in predement...

Abstract— In this paper, a new extended method of multi criteria decision making based on fuzzy-Topsis theory is introduced. fuzzy mcdm algorithm for determining the best choice among all possible choices when the data are fuzzy is also presented. Using a new index leads to procedure for choosing fuzzy ideal and negative ideal solutions directly from the fuzzy data observed alternatives.in this...

پایان نامه :وزارت علوم، تحقیقات و فناوری - دانشگاه شهید چمران اهواز - دانشکده دامپزشکی 1393

مواد ضدعفونی کننده نقش مهمی را در کنترل باکتری های عامل فساد در صنایع غذایی و مکان های عمومی دارند. آب الکترولیز شده بعنوان یک ضدعفونی کننده جدید در سال های اخیر مورد توجه قرار گرفته است. آب الکترولیز شده ایمن، بی خطر، ارزان و بر روی بسیاری از باکتری ها، قارچ ها و ویروس ها موثر است. این مطالعه در دو بخش انجام گرفت. در مطالعه نخست، تاثیر آب الکترولیز خنثیnew))، اسید سیتریک 1%، ترکیب آب الکترولیز...

2005
Marius C. Silaghi

Keyword spotting is an efficient approach for search of relevant recordings in databases of recorded unconstrained speech. Many algorithms have been proposed in the past for this problem and several techniques claim to be very efficient and accurate. Researchers have so far attempted to correctly compare their results by using standardized Receiver Operating Characteristic (ROC) curves, and per...

Journal: :Reumatologia clinica 2010
José Luis Andreu Sánchez

Journal: :Revista portuguesa de cardiologia : orgao oficial da Sociedade Portuguesa de Cardiologia = Portuguese journal of cardiology : an official journal of the Portuguese Society of Cardiology 2003
Rafael Ferreira

735 For the last four decades the diagnosis of MI has been based on the WHO criteria. The definition of MI required the presence of at least two of the following three factors: clinical history of ischemic chest pain; serial changes in ECG; a rise and fall in serum cardiac enzymes. These criteria have been extensively modified by the clinicians in their application: chest pain is often non-spec...

2010
Jean-Sébastien Coron Yevgeniy Dodis Cécile Malinaud Prashant Puniya

The most common way of constructing a hash function (e.g., SHA-1) is to iterate a compression function on the input message. The compression function is usually designed from scratch or made out of a block-cipher. In this paper, we introduce a new security notion for hash-functions, stronger than collision-resistance. Under this notion, the arbitrary length hash function H must behave as a rand...

Journal: :Computers & Industrial Engineering 2015
Czeslaw Smutnicki Jaroslaw Pempera Jaroslaw Rudy Dominik Zelazny

In this paper we propose a new approach, recommended for solving certain class of multi-criteria scheduling problems, with the use of cloud exploration of the solution space supported by finegrained parallel computing. The approach allow us to approximate Pareto front more accurately than other known algorithms in competitive time. To show and check advantageous properties of the proposed appro...

2005
E. F. Clifford

Let a0, . . . , ak−1 be analytic functions on a domain Ω. Let F be a family of meromorphic functions f on Ω such that f 6= 0 and f (k) + ak−1f (k−1) + . . . + a0f 6= 0 on Ω, for all f ∈ F . Then {f ′/f : f ∈ F} is a normal family. Furthermore, let a0, . . . , ak−1 be meromorphic functions on a domain Ω. Let F be a family of meromorphic functions f on Ω such that f 6= 0, f ′ 6= 0 and f (k) + ak−...

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