نتایج جستجو برای: k q

تعداد نتایج: 481117  

2008
Arne Winterhof Christiaan van de Woestijne

with xi ∈ Fq, i.e., as a sum of kth powers of elements of Fq. We can then define the Waring function g(k, q) as the maximal number of summands needed to express all elements of Fq as sums of kth powers. We note that, by an easy argument, we have g(k, q) = g(k, q), where k = gcd(k, q − 1). Hence, we will assume from now on that k divides q − 1. Several authors have established bounds on the valu...

1993
JOHN W. JONES

coming from the cokernels of the rst column. These are cyclic (pro-cyclic in the limit) and are generated by the image of q t. So, lim A(K t)=NA(K n;t) = ?=< (q t ; L t =K t) > where (q t ; L t =K t) is the norm residue symbol of q t for the extension L t =K t. We write Q t for the image of (q t ; L t =K t) under the isomorphism ? ! Z p induced by sending to 1. Note that although Q t is not can...

2009
R. Parimala

There are many good references for this material including [EKM], [L], [Pf] and [S]. 1 Quadratic forms Let k be a field with char k = 2. Definition 1.1. A quadratic form q : V → k on a finite-dimensional vector space V over k is a map satisfying: 1. q(λv) = λ 2 q(v) for v ∈ V , λ ∈ k. 2. The map b q : V × V → k, defined by b q (v, w) = 1 2 [q(v + w) − q(v) − q(w)] is bilinear. We denote a quadr...

Journal: :Journal of Mathematical Analysis and Applications 2023

In 1961, Rankin determined the asymptotic behavior of number Sk,q(x) positive integers n?x for which a given prime q does not divide ?k(n), k-th divisor sum function. By computing associated Euler-Kronecker constant ?k,q, depends on arithmetic certain subfields Q(?q), we obtain second order term in expansion Sk,q(x). Using method developed by Ford, Luca and Moree (2014), determine pairs (k,q) w...

Journal: :Electr. J. Comb. 2004
S. Ole Warnaar

A simple q-analogue of the sum of cubes is given. This answers a question posed in this journal by Garrett and Hummel. The sum of cubes and its q-analogues It is well-known that the first n consecutive cubes can be summed in closed form as n ∑ k=1 k = ( n + 1 2 )2 . Recently, Garrett and Hummel discovered the following q-analogue of this result: n ∑ k=1 qk−1 (1− q)(2− qk−1 − q) (1− q)2(1− q2) =...

1995
Michela Bertolotto Leila De Floriani Paola Magillo

f g overlay q q q q q q q q q q n n O n n k k k O n n 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 Introduction and background

1999
Jurek Czyzowicz Evangelos Kranakis Jorge Urrutia

: H F R Q V LG H U W ZR S U R E OH P V R Q G LV V H F W LR Q V R I S R O\J R Q V ,Q W K H p U V W S U R E OH P ZH F R Q V LG H U W K H P LQ LP X P Q X P E H U R I S LH F H V LQ G LV V H F W LQ J ZLW K U H F W LOLQ H D U J OD V V F X W V D Q P Q d P Q U H F W D Q J OH LQ W R D X Q LW V TX D U H $ U H F W D Q J OH LV F D OOH G V H P L LQ W H J H U LI H LW K H U LW V E D V H R U LW V K H LJ K W LV...

Journal: :Discrete Mathematics 2009
James McLaughlin Andrew V. Sills Peter Zimmer

A pair of sequences (αn(a, k, q),βn(a, k, q)) such that α0(a, k, q) = 1 and βn(a, k, q) = n ∑ j=0 (k/a; q)n−j(k; q)n+j (q; q)n−j(aq; q)n+j αj(a, k, q) is termed a WP-Bailey Pair. Upon setting k = 0 in such a pair we obtain a Bailey pair. In the present paper we consider the problem of “lifting” a Bailey pair to a WPBailey pair, and use some of the new WP-Bailey pairs found in this way to derive...

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