evaluates to n(£) for r = 3. In the published solution [16], It was also noted that Sx{n) = n(£), and, as a consequence, It was conjectured that S2r+i(n) equals the product of („) and a monk polynomial of degree r +1. We show this conjecture to be true, albeit with the modification of discarding the adjec-tival modifier monic. In fact, we show that S2r+l(n) = Pr(n)n(£) and S2r() = Qr()2~\ where...